Observation: Pale yellow precipitate of triiodomethane (CHI₃)
Use: Distinguish methyl ketones from other ketones; ethanol from methanol
19.4 Carboxylic Acids
⚗️ Introduction & Classification
Functional Group: -COOH (Carboxyl group)
General Formula: R-COOH (aliphatic), Ar-COOH (aromatic)
Classification:
• Aliphatic: -COOH attached to alkyl chain
• Aromatic: -COOH attached to benzene ring
• Mono/di/tri-carboxylic acids based on number of -COOH groups
🎯 Key Points:
• Carboxylic acids are weaker than mineral acids but stronger than alcohols
• Only LiAlH₄ reduces acids to alcohols (NaBH₄ doesn’t work)
• Esterification is reversible, catalyzed by acid
Exercises – Complete Solutions
Multiple Choice Questions:
1. Ketones are prepared by the oxidation of:
a. Primary alcohol
b. Secondary alcohol
c. Tertiary alcohol
d. none of these
Answer: (b) Secondary alcohol
Explanation:
• Primary alcohols oxidize to aldehydes then carboxylic acids
• Secondary alcohols oxidize to ketones
• Tertiary alcohols don’t oxidize (no α-hydrogen)
• Oxidizing agents: K₂Cr₂O₇/H⁺ or KMnO₄/H⁺
• Observation: Orange → Green color change
2. Which of the following reagents will react with both aldehydes and ketones?
a. Grignard reagent
b. Tollen’s reagent
c. Fehling’s reagent
d. Benedict’s reagent
Answer: (a) Grignard reagent
Explanation:
• Grignard reagents (R-MgX) react with both aldehydes and ketones via nucleophilic addition
• Tollen’s, Fehling’s, Benedict’s react only with aldehydes (oxidation tests)
• Grignard reaction: R-MgX + R’-CHO → R’-CH(OH)-R (after hydrolysis)
• Grignard reaction: R-MgX + R’-CO-R” → R’-C(OH)(R)-R” (after hydrolysis)
3. Aldehydes are the oxidation product of:
a. p-alcohols (Primary alcohols)
b. s-alcohols (Secondary alcohols)
c. ter-alcohols (Tertiary alcohols)
d. carboxylic acids
Answer: (a) p-alcohols (Primary alcohols)
Explanation:
• Primary alcohols → Aldehydes (partial oxidation)
• Secondary alcohols → Ketones
• Tertiary alcohols → No oxidation (dehydration instead)
• Controlled oxidation needed: Distill aldehyde immediately as it forms (lower bp than alcohol)
(Lactic acid – one more carbon than starting aldehyde)
iv. What is Haloform reaction?
Answer: Haloform reaction is a characteristic test for compounds containing CH₃-CO- group (methyl ketones) or CH₃-CH(OH)- group (ethanol and certain secondary alcohols).
Requirements for positive iodoform test in alcohols:
1. Must have CH₃-CH(OH)- structure
2. Alcohol is first oxidized to carbonyl under test conditions
3. Ethanol → Acetaldehyde (CH₃CHO) → Positive
4. 2° alcohol with CH₃CH(OH)- → Methyl ketone → Positive
ii) Give one reaction that can differentiate between them:
Tollen’s Test or Fehling’s Test:
• Aldehydes: Positive (silver mirror or red ppt)
• Ketones: Negative
• Butanal and 2-methylpropanal will be positive
• Butanone will be negative
iii) Can you use iodoform test to distinguish between them?
Answer: Yes, for some distinctions:
Compound
Structure
Iodoform Test
Reason
Butanal
CH₃CH₂CH₂CHO
Negative
Not CH₃CHO
2-Methylpropanal
(CH₃)₂CHCHO
Negative
Not CH₃CHO
Butanone
CH₃COCH₂CH₃
Positive
Methyl ketone (CH₃CO-)
Iodoform test distinguishes butanone (positive) from both aldehydes (negative).
2. How will you bring about the following conversions:
(i) Ethanol into ethanoic acid
(ii) 2-propanol into propanone
(iii) Butanone into acetic acid
(iv) Ethanol into acetic acid
Answer:
(i)
Ethanol → Ethanoic acid
→
(ii)
2-Propanol → Propanone
→
(iii)
Butanone → Acetic acid
(i) Ethanol into ethanoic acid (CH₃CH₂OH → CH₃COOH):
CH₃CH₂OH + [O] → CH₃CHO + H₂O (Partial oxidation)
CH₃CHO + [O] → CH₃COOH (Complete oxidation)
Reagents: K₂Cr₂O₇/H⁺ or KMnO₄/H⁺ Conditions: Heat with oxidizing agent Note: Two-step oxidation (alcohol → aldehyde → acid)
(ii) 2-propanol into propanone (CH₃CHOHCH₃ → CH₃COCH₃):
CH₃CHOHCH₃ + [O] → CH₃COCH₃ + H₂O
Reagents: K₂Cr₂O₇/H⁺ or KMnO₄/H⁺ Conditions: Heat Note: Secondary alcohol oxidizes directly to ketone
(iii) Butanone into acetic acid (CH₃COCH₂CH₃ → CH₃COOH):
CH₃COCH₂CH₃ + 3[O] → CH₃COOH + CH₃COOH
Reagents: Strong oxidizing agent (hot KMnO₄/H⁺ or conc. HNO₃) Mechanism: Oxidative cleavage of ketone Products: Two molecules of acetic acid (symmetrical cleavage) Note: Ketones require strong oxidation conditions
(iv) Ethanol into acetic acid (Same as (i)):
CH₃CH₂OH → CH₃CHO → CH₃COOH
Alternative route via nitrile:
CH₃CH₂OH → CH₃CH₂Cl → CH₃CH₂CN → CH₃CH₂COOH But this gives propanoic acid, not acetic acid
Direct oxidation is best method
Project Suggestion:
Create an interactive flowchart showing the interconversions between alcohols, aldehydes, ketones, and carboxylic acids, including all reagents and conditions.
• Haloform reaction mechanism • 2,4-DNPH test for identification • Carboxylic acid reactions (esterification, etc.) • Iodoform test applications
Interactive Elements to Include:
• Clickable molecules showing 3D structures
• Animated reaction mechanisms with electron flow
• Flowcharts with hover-over reagent information
• Virtual lab simulations of tests
• Comparative tables with color coding