Practice Stoichiometry MCQs designed for Federal Board students. Enhance your problem-solving skills with topic-specific questions and detailed explanations.
Mole, molar volume, molar mass, and the density of gases
- What is defined as one mole of any substance?
- A) 6.02 x 10²³ molecules
- B) The mass of an atom
- C) One liter of a gas at STP
- D) One gram of a substance
- Answer: A) 6.02 x 10²³ molecules
- The molar mass of a substance is:
- A) The volume of one mole of gas at STP
- B) The mass of one mole of a substance
- C) The number of moles per liter
- D) The density of the substance
- Answer: B) The mass of one mole of a substance
- What is the molar volume of an ideal gas at STP?
- A) 22.4 L
- B) 6.02 L
- C) 1.00 L
- D) 44.8 L
- Answer: A) 22.4 L
- Which statement best defines Avogadro’s number?
- A) The volume occupied by 1 mole of any gas at STP
- B) The number of atoms in 12 g of carbon-12
- C) The atomic mass of any element
- D) The molar mass of a substance
- Answer: B) The number of atoms in 12 g of carbon-12
- The density of a gas at STP can be calculated using:
- A) Density = molar mass / molar volume
- B) Density = molar mass x volume
- C) Density = moles x temperature
- D) Density = molar mass / pressure
- Answer: A) Density = molar mass / molar volume
- If a gas has a molar mass of 44 g/mol, its density at STP would be:
- A) 0.5 g/L
- B) 1.96 g/L
- C) 2.5 g/L
- D) 44 g/L
- Answer: B) 1.96 g/L
- Which gas law explains the relationship between molar volume and temperature?
- A) Boyle’s Law
- B) Charles’s Law
- C) Avogadro’s Law
- D) Ideal Gas Law
- Answer: B) Charles’s Law
- At STP, which of the following gases will have the greatest density?
- A) ( \text{H}_2 )
- B) ( \text{O}_2 )
- C) ( \text{CO}_2 )
- D) ( \text{He} )
- Answer: C) ( \text{CO}_2 )
- One mole of ( \text{H}_2 ) gas at STP occupies:
- A) 11.2 L
- B) 22.4 L
- C) 33.6 L
- D) 44.8 L
- Answer: B) 22.4 L
- The mass of 1 mole of ( \text{CO}_2 ) is approximately:
- A) 28 g
- B) 32 g
- C) 44 g
- D) 16 g
- Answer: C) 44 g
- Which term describes the mass of one mole of any chemical element or compound?
- A) Molecular weight
- B) Molar volume
- C) Atomic mass
- D) Molar mass
- Answer: D) Molar mass
- If a gas has a molar mass of 2 g/mol, what would be its density at STP?
- A) 0.089 g/L
- B) 0.178 g/L
- C) 0.5 g/L
- D) 2 g/L
- Answer: B) 0.178 g/L
- The molar mass of ( \text{O}_2 ) is:
- A) 16 g/mol
- B) 32 g/mol
- C) 8 g/mol
- D) 48 g/mol
- Answer: B) 32 g/mol
- At constant temperature and pressure, the volume of gas is directly proportional to:
- A) Mass
- B) Molar mass
- C) Number of moles
- D) Density
- Answer: C) Number of moles
- What is the volume occupied by 0.5 moles of a gas at STP?
- A) 11.2 L
- B) 22.4 L
- C) 5.6 L
- D) 44.8 L
- Answer: A) 11.2 L
- The density of a gas at STP depends on:
- A) Temperature
- B) Molar mass
- C) Volume
- D) Avogadro’s number
- Answer: B) Molar mass
- Which unit is used to measure molar volume of a gas?
- A) g/mol
- B) mol/L
- C) L/mol
- D) mol/g
- Answer: C) L/mol
- For a given gas, doubling the pressure at constant temperature will:
- A) Double the volume
- B) Halve the volume
- C) Keep the volume constant
- D) Double the density
- Answer: B) Halve the volume
- Which of the following represents the correct molar volume of a gas at STP?
- A) 11.2 L/mol
- B) 22.4 L/mol
- C) 33.6 L/mol
- D) 44.8 L/mol
- Answer: B) 22.4 L/mol
- How many moles are present in 44.8 L of ( \text{CO}_2 ) gas at STP?
- A) 1 mole
- B) 2 moles
- C) 0.5 moles
- D) 3 moles
- Answer: B) 2 moles
- If the molar mass of a gas is known, its density at STP can be calculated by:
- A) Dividing molar mass by Avogadro’s number
- B) Dividing molar mass by molar volume
- C) Multiplying molar mass by volume
- D) Dividing molar mass by temperature
- Answer: B) Dividing molar mass by molar volume
- The mass of 1 mole of ( \text{N}_2 ) gas is:
- A) 14 g
- B) 28 g
- C) 2 g
- D) 32 g
- Answer: B) 28 g
- Which of the following represents Avogadro’s law?
- A) ( P \propto V )
- B) ( V \propto T )
- C) ( V \propto n )
- D) ( P \propto T )
- Answer: C) ( V \propto n )
- The density of ( \text{O}_2 ) gas at STP is approximately:
- A) 1.43 g/L
- B) 0.5 g/L
- C) 2.86 g/L
- D) 1.2 g/L
- Answer: A) 1.43 g/L
- What volume will 1 mole of ( \text{CH}_4 ) gas occupy at STP?
- A) 44.8 L
- B) 22.4 L
- C) 11.2 L
- D) 5.6 L
- Answer: B) 22.4 L
Stoichiometric calculations, mole ratios, and mole-mole calculations
- In a balanced chemical equation, the coefficients represent the:
- A) Mass ratio of reactants and products
- B) Mole ratio of reactants and products
- C) Volume ratio at STP
- D) Molecular weights
- Answer: B) Mole ratio of reactants and products
- What is the mole ratio of H2 to O2 in the reaction 2H2 + O2 → 2H2O?
- A) 1:1
- B) 2:1
- C) 1:2
- D) 3:2
- Answer: B) 2:1
- In the equation N2 + 3H2 → 2NH3 , how many moles of NH3 are produced from 6 moles of H2 ?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 4 moles
- Answer: C) 3 moles
- What is the first step in solving stoichiometric problems?
- A) Calculating the molar mass
- B) Balancing the chemical equation
- C) Converting grams to moles
- D) Determining the limiting reagent
- Answer: B) Balancing the chemical equation
- In a chemical reaction, the mole ratio between two reactants can be determined from:
- A) Their atomic masses
- B) The coefficients in the balanced equation
- C) Their physical states
- D) The reaction rate
- Answer: B) The coefficients in the balanced equation
- Using the balanced equation 4Fe + 3O2 → 2Fe2O3 , how many moles of Fe2O3 ) will form from 4 moles of Fe?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 4 moles
- Answer: B) 2 moles
- In the reaction ( 2KClO3 → 2KCl + 3O2 ), how many moles of O2 ) are produced from 4 moles of KClO3 )?
- A) 2 moles
- B) 3 moles
- C) 4 moles
- D) 6 moles
- Answer: D) 6 moles
- If 2 moles of H2 react with O2 to form water, what is the mole ratio of H2 to H2O?
- A) 1:1
- B) 1:2
- C) 2:2
- D) 2:1
- Answer: A) 1:1
- In a reaction, if the mole ratio between reactant A and product B is 1:3, then 2 moles of A will produce how many moles of B?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 6 moles
- Answer: D) 6 moles
- The stoichiometric coefficient indicates:
- A) The mass of each reactant and product
- B) The energy released in the reaction
- C) The number of moles involved in the reaction
- D) The color of the compounds
- Answer: C) The number of moles involved in the reaction
- In a combustion reaction, if the mole ratio of CH4 to O2 is 1:2, how many moles of O2 are required to completely burn 5 moles of CH4 ?
- A) 2.5 moles
- B) 5 moles
- C) 10 moles
- D) 15 moles
- Answer: C) 10 moles
- Using the equation 2SO2 + O2 → 2SO3, if 2 moles of SO2 react, how many moles of SO3 will be formed?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 4 moles
- Answer: B) 2 moles
- How many moles of HCl are needed to react completely with 1 mole of NaOH in the reaction HCl + NaOH → NaCl + H2O?
- A) 0.5 moles
- B) 1 mole
- C) 1.5 moles
- D) 2 moles
- Answer: B) 1 mole
- In the reaction ( 3H2 + N2 → 2NH3, the mole ratio of N2 to NH3 is:
- A) 1:1
- B) 1:2
- C) 2:3
- D) 3:1
- Answer: B) 1:2
- What is the mole ratio of CO2 ) to C2H4 ) in the complete combustion reaction C2H4 + 3O2→ 2CO2 + 2H2O?
- A) 1:2
- B) 2:1
- C) 1:1
- D) 3:2
- Answer: B) 2:1
- The mole ratio of O2 + CO2 in the reaction CH4 + 2O2 → CO2 + 2H2O is:
- A) 1:1
- B) 1:2
- C) 2:1
- D) 2:3
- Answer: A) 1:1
- In the balanced equation C6H12O6 → 2C2H5OH + 2CO2 , how many moles of CO2 are produced from 1 mole of C6H12O6 ?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 4 moles
- Answer: B) 2 moles
- The equation 2Mg + O2 → 2MgO indicates that 4 moles of Mg will react with how many moles of O2 ?
- A) 1 mole
- B) 2 moles
- C) 3 moles
- D) 4 moles
- Answer: B) 2 mole
- In the reaction H2 + Cl2 → 2HCl, the mole ratio of H2 to HCl is:
- A) 1:1
- B) 1:2
- C) 2:1
- D) 2:2
- Answer: B) 1:2
Solution Stoichiometry
- What is solution stoichiometry used for?
- A) To find gas pressure
- B) To calculate solute amount in a solution
- C) To determine atomic mass
- D) To measure density
- Answer: B) To calculate solute amount in a solution
- In solution stoichiometry, molarity (M) is defined as:
- A) Moles of solute per liter of solution
- B) Moles of solvent per liter of solution
- C) Grams per liter
- D) Moles per kilogram
- Answer: A) Moles of solute per liter of solution
- If 2 moles of NaCl are dissolved in 1 L of water, what is the molarity?
- A) 1 M
- B) 2 M
- C) 0.5 M
- D) 4 M
- Answer: B) 2 M
- The unit of molarity is:
- A) mol/g
- B) mol/L
- C) L/mol
- D) g/mol
- Answer: B) mol/L
- To dilute a solution, you would:
- A) Add more solute
- B) Increase temperature
- C) Add more solvent
- D) Remove solvent
- Answer: C) Add more solvent
- In the equation ( \text{M}_1\text{V}_1 = \text{M}_2\text{V}_2 ), ( \text{M}_2 ) represents:
- A) Final molarity
- B) Initial volume
- C) Final mass
- D) Initial molarity
- Answer: A) Final molarity
- What is the molarity of a solution with 0.5 moles of KCl in 0.25 L?
- A) 1 M
- B) 2 M
- C) 0.25 M
- D) 0.5 M
- Answer: B) 2 M
- If you mix equal volumes of 1 M HCl and 1 M NaOH, the resulting solution is:
- A) Acidic
- B) Neutral
- C) Basic
- D) Salty
- Answer: B) Neutral
- To prepare 1 L of 1 M NaOH, you need:
- A) 1 g NaOH
- B) 10 g NaOH
- C) 40 g NaOH
- D) 0.1 g NaOH
- Answer: C) 40 g NaOH
- If you dilute 1 L of 2 M solution to 2 L, the new molarity is:
- A) 4 M
- B) 2 M
- C) 1 M
- D) 0.5 M
- Answer: C) 1 M
- The molarity of a solution with 3 moles of solute in 3 L is:
- A) 0.5 M
- B) 1 M
- C) 2 M
- D) 3 M
- Answer: B) 1 M
- What volume of 0.5 M H2SO4 is needed for 0.25 moles of H2SO4 ?
- A) 0.5 L
- B) 0.25 L
- C) 1 L
- D) 0.75 L
- Answer: A) 0.5 L
- If 0.2 L of 1 M NaCl is diluted to 1 L, the molarity becomes:
- A) 0.2 M
- B) 0.5 M
- C) 1 M
- D) 0.1 M
- Answer: D) 0.1 M
- How many moles are in 250 mL of 2 M HCl?
- A) 0.25 mol
- B) 0.5 mol
- C) 1 mol
- D) 2 mol
- Answer: B) 0.5 mol
- The equation M1V1 = M2V2 is used for:
- A) Dilution calculations
- B) Gas laws
- C) Solid solubility
- D) Stoichiometry only
- Answer: A) Dilution calculations
- How many liters of 1 M solution contain 2 moles of solute?
- A) 0.5 L
- B) 1 L
- C) 2 L
- D) 3 L
- Answer: C) 2 L
- In solution stoichiometry, molarity is used to calculate:
- A) Mass of a gas
- B) Volume of solution
- C) Concentration of solution
- D) Density
- Answer: C) Concentration of solution
- How many moles are present in 0.5 L of a 1 M solution?
- A) 1 mole
- B) 0.5 mole
- C) 0.25 mole
- D) 2 moles
- Answer: B) 0.5 mole
- To dilute a 2 M solution to 1 M, you need to:
- A) Add twice the amount of solvent
- B) Remove half the solute
- C) Add solute
- D) Heat the solution
- Answer: A) Add twice the amount of solvent
- A 1 M solution of HCl contains:
- A) 1 mole of HCl in 1 L of solution
- B) 1 gram of HCl in 1 L
- C) 2 moles of HCl
- D) 1 mole of HCl in 100 mL
- Answer: A) 1 mole of HCl in 1 L of solution
Limiting and non-limiting reactants:
- What is a limiting reactant?
- A) The reactant that is completely used up
- B) The reactant in excess
- C) The product formed
- D) The reactant that remains
- Answer: A) The reactant that is completely used up
- What is a non-limiting reactant?
- A) Reactant completely used up
- B) Reactant that is left over
- C) Reactant that forms no product
- D) Product formed
- Answer: B) Reactant that is left over
- In a reaction, the limiting reactant determines:
- A) Only the products
- B) The amount of product formed
- C) Reaction rate
- D) The final color of the solution
- Answer: B) The amount of product formed
- If all of a reactant is used up, it is:
- A) Excess reactant
- B) Limiting reactant
- C) Product
- D) Catalyst
- Answer: B) Limiting reactant
- Which reactant is in excess?
- A) Reactant fully consumed
- B) Reactant partially left over
- C) Reactant that forms the most product
- D) Product formed in a reaction
- Answer: B) Reactant partially left over
- How is the limiting reactant identified?
- A) By mass alone
- B) By comparing moles needed vs. moles available
- C) By color of solution
- D) By boiling point
- Answer: B) By comparing moles needed vs. moles available
- What happens to the excess reactant?
- A) It forms all products
- B) It remains after the reaction
- C) It becomes limiting
- D) It is used first
- Answer: B) It remains after the reaction
- Why is the limiting reactant important?
- A) Determines reaction color
- B) Limits amount of product
- C) Increases temperature
- D) Changes reaction rate
- Answer: B) Limits amount of product
- In the reaction 2H2 + O2 → 2H2O, if (O2) is limited, which is in excess?
- A) H2
- B) H2O
- C) O2
- D) All are limiting
- Answer: A) H2
- To find the limiting reactant, you must know:
- A) Molar masses of products
- B) Mole ratios from the balanced equation
- C) Initial pressure of gases
- D) Density of products
- Answer: B) Mole ratios from the balanced equation
Theoretical yield, actual yield, and percent yield:
- What is the theoretical yield?
- A) Actual product formed
- B) Maximum product possible
- C) Excess reactant remaining
- D) Minimum product possible
- Answer: B) Maximum product possible
- What is the actual yield?
- A) Maximum yield calculated
- B) Yield obtained in the lab
- C) Theoretical prediction
- D) Half of the expected yield
- Answer: B) Yield obtained in the lab
- Percent yield is calculated as:
- A) (Theoretical yield / Actual yield) x 100
- B) (Actual yield / Theoretical yield) x 100
- C) Actual yield + Theoretical yield
- D) (Theoretical yield – Actual yield) x 100
- Answer: B) (Actual yield / Theoretical yield) x 100
- If the actual yield is equal to the theoretical yield, percent yield is:
- A) 50%
- B) 100%
- C) 0%
- D) 200%
- Answer: B) 100%
- A reaction’s theoretical yield depends on:
- A) Limiting reactant
- B) Excess reactant
- C) Density
- D) Product color
- Answer: A) Limiting reactant
- Which yield is usually lower due to loss in experiments?
- A) Theoretical yield
- B) Actual yield
- C) Percent yield
- D) Limiting yield
- Answer: B) Actual yield
- If theoretical yield is 10g and actual yield is 7g, percent yield is:
- A) 70%
- B) 140%
- C) 30%
- D) 10%
- Answer: A) 70%
- Percent yield above 100% indicates:
- A) No product was formed
- B) Calculation error or impurities
- C) Perfect reaction efficiency
- D) Theoretical yield exceeded
- Answer: B) Calculation error or impurities
- A low percent yield could indicate:
- A) Very high efficiency
- B) Loss of product during reaction
- C) Overestimation of reactants
- D) Increase in reactant mass
- Answer: B) Loss of product during reaction
- Percent yield is useful to:
- A) Measure reactant purity
- B) Assess reaction efficiency
- C) Calculate reaction color
- D) Determine reaction temperature
- Answer: B) Assess reaction efficiency
Importance of stoichiometry in the production and dosage of medicines:
- Stoichiometry helps in calculating:
- A) Dosage accuracy
- B) Medicine color
- C) Taste of drugs
- D) Shelf life
- Answer: A) Dosage accuracy
- Why is stoichiometry important in medicine production?
- A) To increase weight
- B) For precise formulation
- C) To reduce side effects
- D) For color consistency
- Answer: B) For precise formulation
- In drug formulation, stoichiometry ensures:
- A) Stability of medicine
- B) Accurate active ingredient amount
- C) Reduced cost
- D) Faster production
- Answer: B) Accurate active ingredient amount
- Incorrect stoichiometric calculations can lead to:
- A) Reduced potency
- B) Exact dosage
- C) Increased potency
- D) Only taste change
- Answer: A) Reduced potency
- Which concept is essential for determining the correct medicine dose?
- A) Stoichiometry
- B) Color theory
- C) Surface tension
- D) Filtration
- Answer: A) Stoichiometry
- Stoichiometry helps in avoiding:
- A) Medicine overdose
- B) Improved packaging
- C) Medicine odor
- D) None of the above
- Answer: A) Medicine overdose
- In pharmaceutical production, stoichiometry ensures:
- A) Standardized drug potency
- B) Different potency in each batch
- C) Faster reaction times
- D) Reduced reactivity
- Answer: A) Standardized drug potency
- Accurate stoichiometric calculations in medicine are crucial for:
- A) Patient safety
- B) Reducing cost
- C) Enhancing color
- D) Speeding up reactions
- Answer: A) Patient safety
- Using stoichiometry in medicine dosage prevents:
- A) Side effects from wrong dosages
- B) Faster dissolution
- C) Taste change
- D) Medicine discoloration
- Answer: A) Side effects from wrong dosages
- Proper stoichiometric ratios in drugs affect:
- A) Effectiveness and safety
- B) Flavor of medicine
- C) Cost of production
- D) Packaging quality
- Answer: A) Effectiveness and safety